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Fix #12695 : RangeIndex generated with pd.concat with ignore_index as True #12696

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Fix #12695 : RangeIndex generated with pd.concat with ignore_index as True #12696

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479ab34
Create RangeIndex when ignore_index is False
AnkurDedania Mar 22, 2016
023f5dd
removed setting is_unique and use RangeIndex for comparision
AnkurDedania Mar 22, 2016
850dac4
switched RangeIndex to com._default_index
AnkurDedania Mar 22, 2016
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11 changes: 4 additions & 7 deletions pandas/tools/merge.py
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Original file line number Diff line number Diff line change
Expand Up @@ -992,7 +992,7 @@ def get_result(self):
# names (because set via the 'key' argument in the 'concat'
# function call. If that's not the case, use the series names
# as column names
if (columns.equals(Index(np.arange(len(self.objs)))) and
if (columns.equals(com._default_index(len(self.objs))) and
not self.ignore_index):
columns = np.array([data[i].name
for i in range(len(data))],
Expand Down Expand Up @@ -1079,8 +1079,7 @@ def _get_concat_axis(self):
if self.axis == 0:
indexes = [x.index for x in self.objs]
elif self.ignore_index:
idx = Index(np.arange(len(self.objs)))
idx.is_unique = True # arange is always unique
idx = com._default_index(len(self.objs))
return idx
elif self.keys is None:
names = []
Expand All @@ -1092,8 +1091,7 @@ def _get_concat_axis(self):
if x.name is not None:
names.append(x.name)
else:
idx = Index(np.arange(len(self.objs)))
idx.is_unique = True
idx = com._default_index(len(self.objs))
return idx

return Index(names)
Expand All @@ -1103,8 +1101,7 @@ def _get_concat_axis(self):
indexes = [x._data.axes[self.axis] for x in self.objs]

if self.ignore_index:
idx = Index(np.arange(sum(len(i) for i in indexes)))
idx.is_unique = True
idx = com._default_index(sum(len(i) for i in indexes))
return idx

if self.keys is None:
Expand Down