AtCoder/ABC186

atcoder/abc186/A/main.cpp

@@ -0,0 +1,17 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+using ll = int64_t;
+using ff = long double;
+
+int main() {
+    ios_base::sync_with_stdio(false);
+    cin.tie(0); cout.tie(0);
+
+    int N, W;
+    cin >> N >> W;
+    int C = N / W;
+    cout << C << endl;
+
+    return 0;
+}

atcoder/abc186/B/main.cpp

@@ -0,0 +1,25 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+using ll = int64_t;
+using ff = long double;
+
+int main() {
+    ios_base::sync_with_stdio(false);
+    cin.tie(0); cout.tie(0);
+
+    int H, W;
+    cin >> H >> W;
+
+    vector<int> A(H * W);
+    for (int i = 0; i < H * W; ++i) {
+        cin >> A[i];
+    }
+    int mini = *min_element(A.begin(), A.end());
+    int ans = accumulate(A.begin(), A.end(), 0, [&](int s, int v) {
+        return s + (v - mini);
+    });
+    cout << ans << endl;
+
+    return 0;
+}

atcoder/abc186/C/main.cpp

@@ -0,0 +1,39 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+using ll = int64_t;
+using ff = long double;
+
+bool contains7_on_10base(int N) {
+    while (N > 0) {
+        if (N % 10 == 7) return true;
+        N /= 10;
+    }
+    return false;
+}
+
+bool contains7_on_8base(int N) {
+    while (N > 0) {
+        if (N % 8 == 7) return true;
+        N /= 8;
+    }
+    return false;
+}
+
+int main() {
+    ios_base::sync_with_stdio(false);
+    cin.tie(0); cout.tie(0);
+
+    int N;
+    cin >> N;
+
+    int ans = 0;
+    for (int i = 1; i <= N; ++i) {
+        if (contains7_on_10base(i)) continue;
+        if (contains7_on_8base(i)) continue;
+        ++ans;
+    }
+    cout << ans << endl;
+
+    return 0;
+}

atcoder/abc186/D/main.cpp

@@ -0,0 +1,34 @@
+#include <bits/stdc++.h>
+
+using namespace std;
+using ll = int64_t;
+using ff = long double;
+
+int main() {
+    ios_base::sync_with_stdio(false);
+    cin.tie(0); cout.tie(0);
+
+    int N;
+    vector<ll> A;
+
+    cin >> N;
+    A.assign(N, 0);
+    for (auto &a : A) cin >> a;
+
+    sort(A.begin(), A.end());
+    ll rhs = 0;
+    for (int i = 0; i < N; ++i) {
+        rhs += (N - i) * A[i];
+    }
+    ll lhs = 0;
+    for (int i = N - 1; i >= 0; --i) {
+        if (i + 1 < N) {
+            A[i] += A[i+1];
+        }
+        lhs += A[i];
+    }
+    ll ans = lhs - rhs;
+    cout << ans << endl;
+
+    return 0;
+}