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BUG: preserve fold in Timestamp.replace #37644
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30f7275
BUG: preserve fold in Timestamp.replace
AlexKirko b2745e1
DOC: add whatsnew
AlexKirko 096ee9b
TST: add test
AlexKirko b9fa491
DOC: mirror doc change for NaT
AlexKirko b4c4127
TST: move the test
AlexKirko 7c2f782
TST: improve test readability
AlexKirko 2ca31ca
TST: incorporate reviewer suggestions
AlexKirko 4719697
TST: replace second instead of fold
AlexKirko ada4d94
TST: tzinfo instead of tz in the test
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A few things:
fold
set correctly. This could fail for reasons unrelated to the thing you are testing.fold=0
→fold=0
andfold=1
→fold=1
.replace(tzinfo=tz)
, you are creating an identical timestamp. I suspect that it would be very reasonable for a future version of Python or Pandas to optimize that case and simply return the originalTimestamp
/datetime
if nothing is changed, making this not an ideal test.Timestamp
, executingreplace
and accessing the.fold
property. I would do these on separate lines.Probably something more like this:
Where
fold
is parameterized over[0, 1]
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@pganssle Thanks! I had made changes to the test, instead testing our behavior versus
datetime
, but your suggestion makes more sense. This way, we don't care whether datetime works properly (on the slim chance that it breaks). Introduced the changes. Hope you don't mind me keeping the OP timezone.Please take a look at the new version.
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You can make the replacing of tzinfo work as a reasonable test if you change to the other timezone with the same time of DST change, e.g Moscow to Novosibirsk
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@AlexeyDmitriev That would work, but also make the test a bit less readable (we'd need to comment that we are swapping between two DST-zones, and both times are in a fold). I think leaving the current test should be okay.