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TST: Period with Timestamp overflow #34755

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Oct 5, 2020
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29 changes: 29 additions & 0 deletions pandas/tests/scalar/period/test_period.py
Original file line number Diff line number Diff line change
Expand Up @@ -6,6 +6,7 @@

from pandas._libs.tslibs import iNaT, period as libperiod
from pandas._libs.tslibs.ccalendar import DAYS, MONTHS
from pandas._libs.tslibs.np_datetime import OutOfBoundsDatetime
from pandas._libs.tslibs.parsing import DateParseError
from pandas._libs.tslibs.period import INVALID_FREQ_ERR_MSG, IncompatibleFrequency
from pandas._libs.tslibs.timezones import dateutil_gettz, maybe_get_tz
Expand Down Expand Up @@ -767,6 +768,34 @@ def test_period_deprecated_freq(self):
assert isinstance(p1, Period)
assert isinstance(p2, Period)

@pytest.mark.parametrize("bound, offset", [(Timestamp.min, -1), (Timestamp.max, 1)])
def test_start_time_and_end_time_bounds(self, bound, offset):
# GH #13346
period = Period(
year=bound.year,
month=bound.month,
day=bound.day,
hour=bound.hour,
minute=bound.minute,
second=bound.second - offset,
freq="us",
)
period.start_time
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Would be great to assert what this operation returns. assert period.start_time == ...

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I've tried write a better line for this one, but didn't managed.

period.end_time
period = Period(
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Could you create a separate test function for this?

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done in the last PR

year=bound.year,
month=bound.month,
day=bound.day,
hour=bound.hour,
minute=bound.minute,
second=bound.second + offset,
freq="us",
)
with pytest.raises(OutOfBoundsDatetime, match="Out of bounds nanosecond"):
period.start_time
with pytest.raises(OutOfBoundsDatetime, match="Out of bounds nanosecond"):
period.end_time

def test_start_time(self):
freq_lst = ["A", "Q", "M", "D", "H", "T", "S"]
xp = datetime(2012, 1, 1)
Expand Down