DOC: Updated the DataFrame.assign docstring

pandas/core/frame.py

@@ -3250,48 +3250,34 @@ def assign(self, **kwargs):
 
         Examples
         --------
-        >>> df = pd.DataFrame({'A': range(1, 11), 'B': np.random.randn(10)})
+        >>> df = pd.DataFrame({'temp_c': (17.0, 25.0)},
+                                index=['Portland', 'Berkeley'])
+                  temp_c
+        Portland    17.0
+        Berkeley    25.0
 
         Where the value is a callable, evaluated on `df`:
-
-        >>> df.assign(ln_A = lambda x: np.log(x.A))
-            A         B      ln_A
-        0   1  0.426905  0.000000
-        1   2 -0.780949  0.693147
-        2   3 -0.418711  1.098612
-        3   4 -0.269708  1.386294
-        4   5 -0.274002  1.609438
-        5   6 -0.500792  1.791759
-        6   7  1.649697  1.945910
-        7   8 -1.495604  2.079442
-        8   9  0.549296  2.197225
-        9  10 -0.758542  2.302585
-
-        Where the value already exists and is inserted:
-
-        >>> newcol = np.log(df['A'])
-        >>> df.assign(ln_A=newcol)
-            A         B      ln_A
-        0   1  0.426905  0.000000
-        1   2 -0.780949  0.693147
-        2   3 -0.418711  1.098612
-        3   4 -0.269708  1.386294
-        4   5 -0.274002  1.609438
-        5   6 -0.500792  1.791759
-        6   7  1.649697  1.945910
-        7   8 -1.495604  2.079442
-        8   9  0.549296  2.197225
-        9  10 -0.758542  2.302585
-
-        Where the keyword arguments depend on each other
-
-        >>> df = pd.DataFrame({'A': [1, 2, 3]})
-
-        >>> df.assign(B=df.A, C=lambda x:x['A']+ x['B'])
-            A  B  C
-         0  1  1  2
-         1  2  2  4
-         2  3  3  6
+        >>> df.assign(temp_f=lambda x: x.temp_c * 9 / 5 + 32)
+                  temp_c  temp_f
+        Portland    17.0    62.6
+        Berkeley    25.0    77.0
+
+        Alternatively, the same behavior can be achieved by directly
+        referencing an existing Series or list-like:
+        >>> newcol = df['temp_c'] * 9 / 5 + 32
+        >>> df.assign(temp_f=newcol)
+                  temp_c  temp_f
+        Portland    17.0    62.6
+        Berkeley    25.0    77.0
+
+        In Python 3.6+, you can create multiple columns within the same assign
+        where one of the columns depends on another one defined within the same
+        assign:
+        >>> df.assign(temp_f=lambda x: x['temp_c'] * 9 / 5 + 32,
+                        temp_k=lambda x: (x['temp_f'] +  459.67) * 5 / 9)
+                  temp_c  temp_f  temp_k
+        Portland    17.0    62.6  290.15
+        Berkeley    25.0    77.0  298.15
         """
         data = self.copy()