BUG/TST: Calling shift on a DatetimeIndex of length 0 returns an Index in… #13026
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…stead of a DatetimeIndex
| # GH 9903 | ||
| for tz in [None, 'US/Eastern', 'Asia/Tokyo']: | ||
| idx = pd.DatetimeIndex([], name='xxx', tz=tz) | ||
| tm.assert_index_equal(idx.shift(0, freq='H'), idx) |
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I think you want exact=True in all the assert_index_equal calls here. By default, assert_index_equal only asserts that both values are instances of Index.
EDIT: I was looking at an older version of pandas. It looks like this is no longer true on master. Carry on :).
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👍 |
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thanks @sinhrks |
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git diff upstream/master | flake8 --diffwhatsnew entryNo what's new as the fixed timing is unclear.