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This same error is given if we provide freq as a tuple like freq=('T', 5)
So either the code can't handle mult != 1 (in which case the docstring is wrong). Or, if the docstring is correct (the code can handle a mult != 1) then the exception is wrong.
(For my own work, I would love to be able to use arbitrary-length Period instances. Here's a related StackOverflow question that I have just asked: Irregular, non-contiguous Periods in Pandas)
(I'm using Pandas 0.12)
The text was updated successfully, but these errors were encountered:
(I love Pandas! Great work! One small issue...)
The docstring for the
Period
constructor reads:i.e. the docstring says that
freq
can be multiples of a period code (e.g. 5 minutes).But if we try to use
mult != 1
then we get an exception:This same error is given if we provide
freq
as a tuple likefreq=('T', 5)
So either the code can't handle
mult != 1
(in which case the docstring is wrong). Or, if the docstring is correct (the code can handle amult != 1
) then the exception is wrong.(For my own work, I would love to be able to use arbitrary-length
Period
instances. Here's a related StackOverflow question that I have just asked: Irregular, non-contiguous Periods in Pandas)(I'm using Pandas 0.12)
The text was updated successfully, but these errors were encountered: