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Displayed precision of float in presence of np.inf #24861

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@glemaitre

Description

@glemaitre

Code Sample, a copy-pastable example if possible

import numpy as np
import pandas as pd

print(
    pd.Series([1., 2.2222, np.inf]).round(1)
)

Problem description

The display of floating precision in a dataframe and serie could be improved in the presence of np.inf.
My expectation would be that np.inf would induce the same behavior than 'NaN.

Expected Output

0    1.0
1    2.2
2     inf
dtype: float64

Instead, the following result is obtained:

0    1.000000
1    2.200000
2         inf
dtype: float64

Note that this is the result in presence of a NaN:

0    1.0
1    2.2
2    NaN
dtype: float64

Output of pd.show_versions()

INSTALLED VERSIONS
------------------
commit: None
python: 3.6.7.final.0
python-bits: 64
OS: Linux
OS-release: 4.15.0-43-generic
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8

pandas: 0.23.4
pytest: None
pip: 10.0.1
setuptools: 39.2.0
Cython: None
numpy: 1.14.5
scipy: 1.1.0
pyarrow: None
xarray: None
IPython: 6.4.0
sphinx: None
patsy: 0.5.0
dateutil: 2.7.3
pytz: 2018.4
blosc: None
bottleneck: None
tables: None
numexpr: None
feather: None
matplotlib: 3.0.2
openpyxl: None
xlrd: None
xlwt: None
xlsxwriter: None
lxml: None
bs4: None
html5lib: 1.0.1
sqlalchemy: None
pymysql: None
psycopg2: None
jinja2: 2.10
s3fs: None
fastparquet: None
pandas_gbq: None
pandas_datareader: None

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