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LeetCode Problam #29

Answered by iamAntimPal
IamShiwangi asked this question in Q&A
Mar 21, 2025 · 1 comments · 1 reply
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WITH
  InsuranceWithCounts AS (
    SELECT
      tiv_2016,
      COUNT(*) OVER(PARTITION by tiv_2015) AS tiv_2015_count,
      COUNT(*) OVER(PARTITION by lat, lon) AS city_count
    FROM Insurance
  )
SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
FROM InsuranceWithCounts
WHERE tiv_2015_count > 1
  AND city_count = 1;

Explanation

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@IamShiwangi
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