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If a string should be expanded (e.g. string concatenation, function "changeBuffer()") and there is no enough memory for a new size (realloc() fails), the old memory is not deallocated, but the pointer is ovewritten with zero. This is a memory leak. With this change, the string will retain its old value and will be safely disposed; changeBuffer() returns an error.
realloc() is called with newSize > 0 (at least 16), so newbuffer==0 means the old memory was not deallocated. Therefore, the pointer should still point to the old buffer. This change should resolve issue #3516.