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Value-set dereference: use cond_exprt to avoid quadratic guards #4555

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67 changes: 46 additions & 21 deletions src/pointer-analysis/value_set_dereference.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -107,12 +107,12 @@ exprt value_set_dereferencet::dereference(const exprt &pointer)
may_fail=true;
}

exprt failure_value;
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I find it too non-trivial to check that failure_value is never used uninitialised. See comment below.


if(may_fail)
{
// first see if we have a "failed object" for this pointer

exprt failure_value;

if(
const symbolt *failed_symbol =
dereference_callback.get_or_create_failed_symbol(pointer))
Expand All @@ -138,36 +138,61 @@ exprt value_set_dereferencet::dereference(const exprt &pointer)
failure_value=symbol.symbol_expr();
failure_value.set(ID_C_invalid_object, true);
}

valuet value;
value.value=failure_value;
value.pointer_guard=true_exprt();
values.push_front(value);
}

// now build big case split, but we only do "good" objects

exprt value=nil_exprt();

for(std::list<valuet>::const_iterator
it=values.begin();
it!=values.end();
it++)
optionalt<exprt> value_without_condition;
cond_exprt cond({}, type, true);
for(const auto &alias_value : values)
{
if(it->value.is_not_nil())
if(alias_value.value.is_not_nil())
{
if(value.is_nil()) // first?
value=it->value;
if(alias_value.pointer_guard.is_false())
{
INVARIANT(
!value_without_condition.has_value(),
"can't discriminate between two different catch-all aliases");
value_without_condition = alias_value.value;
}
else
value=if_exprt(it->pointer_guard, it->value, value);
{
cond.add_case(alias_value.pointer_guard, alias_value.value);
INVARIANT(
alias_value.value.type() == type,
"deref value types should match the pointer being derefd");
}
}
}

#if 0
std::cout << "R: " << format(value) << "\n\n";
#endif
// I'd like to put an invariant here that values without a pointer guard, such
// as integer_address, cannot co-occur with failed objects, but this isn't the
// case. There's no way to write a GOTO condition to discriminate between the
// two however, so purely by historical accident, the failed object takes
// precedence:

if(may_fail || value_without_condition.has_value())
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Can't we just combine value_without_condition and failure_value into a single expression?

{
// The cases must be disjoint, so add
// "!(p == &o1 || p == &o2 || p == &o3 || ...) => failure-value"
exprt::operandst other_case_conditions;
for(std::size_t i = 0; i < cond.get_n_cases(); ++i)
other_case_conditions.push_back(cond.condition(i));
cond.add_case(
not_exprt(disjunction(other_case_conditions)),
may_fail ? failure_value : *value_without_condition);
}

return value;
#if 0
std::cout << "R: " << format(cond) << "\n\n";
#endif

if(cond.get_n_cases() == 0)
return nil_exprt();
else if(cond.get_n_cases() == 1)
return cond.value(0);
else
return std::move(cond);
}

/// Check if the two types have matching number of ID_pointer levels, with
Expand Down