Add tests for the bitwise operators (and, or, not, xor)

Author: NlightNFotis

regression/cbmc-incr-smt2/bitvector-bitwise-operators/bitwise.desc

@@ -0,0 +1,11 @@
+CORE
+bitwise_ops.c
+--incremental-smt2-solver 'z3 --smt2 -in' --slice-formula
+\[main\.assertion\.1\] line \d+ This is going to fail for bit-opposites: FAILURE
+\[main\.assertion\.2\] line \d+ This is going to hold for all values != 0: SUCCESS
+\[main\.assertion\.3\] line \d+ This is going to fail for the same value in A and B: FAILURE
+\[main\.assertion\.4\] line \d+ This will fail for the the same value in A and B: FAILURE
+^EXIT=10$
+^SIGNAL=0$
+--
+--

regression/cbmc-incr-smt2/bitvector-bitwise-operators/bitwise_ops.c

@@ -0,0 +1,24 @@
+int main()
+{
+  int a;
+  int b;
+
+  __CPROVER_assume(a != 0);
+
+  // This if going to be failing for values of `0000` and `1111`,
+  // as the bitwise-& of that will produce 0, failing this assertion.
+  __CPROVER_assert(a & b, "This is going to fail for bit-opposites");
+  // This will always be true, because bitwise-or allows a 1 at a bit
+  // that either A or B have set as one, and with an assumption of
+  // a != 0, there's always going to be at least 1 bit set, allowing
+  // the assertion below to evaluate to true.
+  __CPROVER_assert(a | b, "This is going to hold for all values != 0");
+  // This will fail for the same value, as an XOR of the bits will
+  // result in `0`, resulting in the assertion failure.
+  __CPROVER_assert(
+    a ^ b, "This is going to fail for the same value in A and B");
+  // This will fail for the exact same value of A and B, as 
+  // NOT(A) will flip all the bits, resulting in the equality
+  // below to be false for the assertion.
+  __CPROVER_assert(~a == b, "This will fail for the the same value in A and B");
+}