Skip to content

Update 3n+1.py #996

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 4 commits into from
Jul 13, 2019
Merged
Changes from 3 commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
43 changes: 28 additions & 15 deletions maths/3n+1.py
Original file line number Diff line number Diff line change
@@ -1,19 +1,32 @@
def main():
def n31(a):# a = initial number
c = 0
l = [a]
while a != 1:
if a % 2 == 0:#if even divide it by 2
a = a // 2
elif a % 2 == 1:#if odd 3n+1
a = 3*a +1
c += 1#counter
l += [a]
from typing import Tuple, List

def n31(a: int) -> Tuple[List[int], int]:
"""
Returns Collatz sequence of a number
Copy link
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

This comment says that we are only returning the sequence but we are returning the sequence and its length.

Copy link
Contributor Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

updated docstring

>>> n31(4)
([4, 2, 1], 3)
"""

if not isinstance(a, int):
raise TypeError('Must be int, not {0}'.format(type(a).__name__))
if a < 1:
raise ValueError('Given integer must be greater than 1, not {0}'.format(a))

return l , c
print(n31(43))
print(n31(98)[0][-1])# = a
print("It took {0} steps.".format(n31(13)[1]))#optional finish
counter = 0
path = [a]
while a != 1:
if a % 2 == 0:
a = a // 2
else:
a = 3*a +1
counter += 1
path += [a]
return path, counter + 1
Copy link
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Would it also work to return path, len(path) ?

Copy link
Contributor Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Yes, that is more elegant, thanks!


def main():
num = 4
path , length = n31(num)
print("The Collatz sequence of {0} took {1} steps. \nPath: {2}".format(num,length, path))
Copy link
Member

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

You can drop the 0, 1, and 2 here and drop the 0 in the raise statements above.


if __name__ == '__main__':
main()