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add Levinstein distance with Dynamic Programming: up -> down approach #7171
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alexpantyukhin:min_distance_dp_up_bottom
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add Levinstein distance with Dynamic Programming: up -> down approach
alexpantyukhin 2667746
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Merge branch 'min_distance_dp_up_bottom' of https://github.com/alexpa…
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Update dynamic_programming/min_distance_up_bottom.py
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Original file line number | Diff line number | Diff line change |
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""" | ||
Author : Alexander Pantyukhin | ||
Date : October 14, 2022 | ||
This is implementation Dynamic Programming up bottom approach to find edit distance. | ||
The aim is to demonstate up bottom approach for solving the task. | ||
The implementation was tested on the leetcode: https://leetcode.com/problems/edit-distance/ | ||
""" | ||
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""" | ||
Levinstein distance | ||
Dynamic Programming: up -> down. | ||
""" | ||
def min_distance_up_bottom(word1: str, word2: str) -> int: | ||
""" | ||
>>> min_distance_up_bottom("intention", "execution") | ||
5 | ||
>>> min_distance_up_bottom("intention", "") | ||
9 | ||
>>> min_distance_up_bottom("", "") | ||
0 | ||
>>> min_distance_up_bottom("zooicoarchaeologist", "zoologist") | ||
10 | ||
""" | ||
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from functools import lru_cache | ||
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len_word1 = len(word1) | ||
len_word2 = len(word2) | ||
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@lru_cache(maxsize=None) | ||
def min_distance(index1, index2): | ||
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# if first word index is overflow - delete all from the second word | ||
if index1 >= len_word1: | ||
return len_word2 - index2 | ||
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# if second word index is overflow - delete all from the first word | ||
if index2 >= len_word2: | ||
return len_word1 - index1 | ||
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# if letters on the current positions are identical - no diff. | ||
diff = 0 | ||
if word1[index1] != word2[index2]: | ||
diff = 1 | ||
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return min( | ||
1 + min_distance(index1 + 1, index2), | ||
1 + min_distance(index1, index2 + 1), | ||
diff + min_distance(index1 + 1, index2 + 1) | ||
) | ||
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return min_distance(0, 0) | ||
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if __name__ == "__main__": | ||
import doctest | ||
doctest.testmod() |
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