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add Levinstein distance with Dynamic Programming: up -> down approach #7171
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""" | ||
Author : Alexander Pantyukhin | ||
Date : October 14, 2022 | ||
This is implementation Dynamic Programming up bottom approach to find edit distance. | ||
The aim is to demonstate up bottom approach for solving the task. | ||
The implementation was tested on the leetcode: https://leetcode.com/problems/edit-distance/ | ||
""" | ||
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""" | ||
Levinstein distance | ||
Dynamic Programming: up -> down. | ||
""" | ||
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def min_distance_up_bottom(word1: str, word2: str) -> int: | ||
""" | ||
>>> min_distance_up_bottom("intention", "execution") | ||
5 | ||
>>> min_distance_up_bottom("intention", "") | ||
9 | ||
>>> min_distance_up_bottom("", "") | ||
0 | ||
>>> min_distance_up_bottom("zooicoarchaeologist", "zoologist") | ||
10 | ||
""" | ||
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from functools import lru_cache | ||
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len_word1 = len(word1) | ||
len_word2 = len(word2) | ||
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@lru_cache(maxsize=None) | ||
def min_distance(index1: int, index2: int) -> int: | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. As there is no test file in this pull request nor any test function or class in the file There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. As there is no test file in this pull request nor any test function or class in the file There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. As there is no test file in this pull request nor any test function or class in the file There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. As there is no test file in this pull request nor any test function or class in the file |
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# if first word index is overflow - delete all from the second word | ||
if index1 >= len_word1: | ||
return len_word2 - index2 | ||
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# if second word index is overflow - delete all from the first word | ||
if index2 >= len_word2: | ||
return len_word1 - index1 | ||
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# if letters on the current positions are identical - no diff. | ||
diff = 0 | ||
if word1[index1] != word2[index2]: | ||
diff = 1 | ||
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return min( | ||
1 + min_distance(index1 + 1, index2), | ||
1 + min_distance(index1, index2 + 1), | ||
diff + min_distance(index1 + 1, index2 + 1), | ||
) | ||
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return min_distance(0, 0) | ||
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if __name__ == "__main__": | ||
import doctest | ||
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doctest.testmod() |
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