Added 2 new algorythms (decrypt message, censor) #5883
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| Original file line number | Diff line number | Diff line change | ||||
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| @@ -0,0 +1,21 @@ | ||||||
| def average_welford(values): | ||||||
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| """ | ||||||
| >>> average_welford([1, 2, 3, 4, 5]) | ||||||
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| 3.0 | ||||||
| >>> average_welford([1.2329435, 2.209462409, 3.230925, 4.47626462, 5.2938759204]) | ||||||
| 3.2886942898799996 | ||||||
| >>> average_welford([-57386462.2329435, 2246262.209462409, 4632463.230925, 856737354.47626462, -243664265.2938759204]) | ||||||
| 112513070.4779665 | ||||||
| """ | ||||||
| avg = 0.0 | ||||||
| """while looping through the list, | ||||||
| we calculate the average of the | ||||||
| current element and the average | ||||||
| of the elements before it""" | ||||||
| for index in range(0, len(values)): | ||||||
| avg += (values[index]-avg)/(index+1) | ||||||
| return avg | ||||||
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| if __name__ == "__main__": | ||||||
| import doctest | ||||||
| doctest.testmod() | ||||||
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Please provide return type hint for the function:
average_welford. If the function does not return a value, please provide the type hint as:def function() -> None:Please provide type hint for the parameter:
values