Skip to content

Added solution for Project Euler problem 72 #3122

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 7 commits into from
Oct 16, 2020
Merged
45 changes: 45 additions & 0 deletions project_euler/problem_072/sol2.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,45 @@
"""
Project Euler Problem 72: https://projecteuler.net/problem=72

Consider the fraction, n/d, where n and d are positive integers. If n<d and HCF(n,d)=1,
it is called a reduced proper fraction.

If we list the set of reduced proper fractions for d ≤ 8 in ascending order of size,
we get:

1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2,
4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8

It can be seen that there are 21 elements in this set.

How many elements would be contained in the set of reduced proper fractions
for d ≤ 1,000,000?
"""


def solution(limit: int = 1000000) -> int:
"""
Return the number of reduced proper fractions with denominator less than limit.
>>> solution(8)
21
>>> solution(1000)
304191
"""
primes = set(range(3, limit, 2))
primes.add(2)
for p in range(3, limit, 2):
if p not in primes:
continue
primes.difference_update(set(range(p * p, limit, p)))

phi = [float(n) for n in range(limit + 1)]

for p in primes:
for n in range(p, limit + 1, p):
phi[n] *= 1 - 1 / p

return int(sum(phi[2:]))


if __name__ == "__main__":
print(f"{solution() = }")