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1 change: 1 addition & 0 deletions project_euler/problem_47/__init__.py
Original file line number Diff line number Diff line change
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111 changes: 111 additions & 0 deletions project_euler/problem_47/sol1.py
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"""
Combinatoric selections

Problem 47

The first two consecutive numbers to have two distinct prime factors are:

14 = 2 × 7
15 = 3 × 5

The first three consecutive numbers to have three distinct prime factors are:

644 = 2² × 7 × 23
645 = 3 × 5 × 43
646 = 2 × 17 × 19.

Find the first four consecutive integers to have four distinct prime factors each.
What is the first of these numbers?
"""

from functools import lru_cache


def unique_prime_factors(n: int) -> set:
"""
Function to find unique prime factors of an integer.
Tests include sorting because only the set really matters,
not the order in which it is produced.
>>> set(sorted(unique_prime_factors(14)))
{2, 7}
>>> set(sorted(unique_prime_factors(644)))
{2, 23, 7}
>>> set(sorted(unique_prime_factors(646)))
{17, 2, 19}
"""
i = 2
factors = set()
while i * i <= n:
if n % i:
i += 1
else:
n //= i
factors.add(i)
if n > 1:
factors.add(n)
return factors


@lru_cache(maxsize=5)
def upf_len(num: int) -> int:
"""
Helper function to memoize upf() length results for a given value.
>>> upf_len(14)
2
"""
return len(unique_prime_factors(num))


def equality(iterable: list) -> bool:
"""
Check equality of ALL elements in an interable.
>>> equality([1,2,3,4])
False
>>> equality([2,2,2,2])
True
"""
if iterable[:1]:
return iterable[1:] == iterable[:-1]


def run(n: int) -> list:
"""
Function that runs core process to find problem solution.
>>> run(3)
[644, 645, 646]
"""

i = 2
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Suggested change
i = 2

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The i kind of needs to be there. It's used to help generate a series of consecutive values.

If i is 2, then group = [2, 3, 4, 5] for n = 4
If i is 3, then group = [3, 4, 5, 6] for n = 4
If i is 4, then group = [4, 5, 6, 7] for n = 4
etc.

I can change the variable to q or something a little less ambiguous, like base. Something like:

base = 2
<...snip...>
group = list(map(lambda x: base + x, [i for i in range(n)]))


success = 0

while success < 1:
# Increment each value of a generated range
group = list(map(lambda x, y=i: y + x, [i for i in range(n)]))

# Run elements through out unique_prime_factors function
# Append our target number to the end.
checker = list(map(upf_len, group))
checker.append(n)

# If all numbers in the list are euqal, increment our success variable
# to exit the while loop and return the current group of numbers.
if equality(checker):
success += 1
return group
i += 1


def solution(N: int = 4) -> int:
"""Returns the first value of the first four consecutive integers to have four
distinct prime factors each.
>>> solution()
134043
"""
results = run(N)
if len(results) > 0:
return results[0]


if __name__ == "__main__":
print(solution())