Problem 16 Added

Project Euler/Problem 16/sol1.py

@@ -0,0 +1,15 @@
+power = int(input("Enter the power of 2: "))
+num = 2**power
+
+string_num = str(num)
+
+list_num = list(string_num)
+
+sum_of_num = 0
+
+print("2 ^",power,"=",num)
+
+for i in list_num:
+    sum_of_num += int(i)
+
+print("Sum of the digits are:",sum_of_num)

Project Euler/Problem 20/sol1.py

@@ -0,0 +1,27 @@
+# Finding the factorial.
+def factorial(n):
+    fact = 1
+    for i in range(1,n+1):
+        fact *= i
+    return fact
+
+# Spliting the digits and adding it.
+def split_and_add(number):
+    sum_of_digits = 0
+    while(number>0):
+        last_digit = number % 10
+        sum_of_digits += last_digit
+        number = int(number/10) # Removing the last_digit from the given number.
+    return sum_of_digits
+
+# Taking the user input.
+number = int(input("Enter the Number: "))
+
+# Assigning the factorial from the factorial function.
+factorial = factorial(number)
+
+# Spliting and adding the factorial into answer.
+answer = split_and_add(factorial)
+
+# Printing the answer.
+print(answer)

Project Euler/README.md

@@ -49,3 +49,10 @@ PROBLEMS:
     Using the rule above and starting with 13, we generate the following sequence:
     13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1
     Which starting number, under one million, produces the longest chain?
+
+16. 2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
+    What is the sum of the digits of the number 2^1000?
+20. n! means n × (n − 1) × ... × 3 × 2 × 1
+    For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,
+    and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
+    Find the sum of the digits in the number 100!