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added solution 7 for problem_01 #1416
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""" | ||
Problem Statement: | ||
If we list all the natural numbers below 10 that are multiples of 3 or 5, | ||
we get 3,5,6 and 9. The sum of these multiples is 23. | ||
Find the sum of all the multiples of 3 or 5 below N. | ||
""" | ||
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def solution(n): | ||
"""Returns the sum of all the multiples of 3 or 5 below n. | ||
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>>> solution(3) | ||
0 | ||
>>> solution(4) | ||
3 | ||
>>> solution(10) | ||
23 | ||
>>> solution(600) | ||
83700 | ||
""" | ||
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result = 0 | ||
for i in range(n): | ||
if i % 3 == 0: | ||
result += i | ||
elif i % 5 == 0: | ||
result += i | ||
return result | ||
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if __name__ == "__main__": | ||
print(solution(int(input().strip()))) |
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""" | ||
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Problem: | ||
Each new term in the Fibonacci sequence is generated by adding the previous two | ||
terms. By starting with 1 and 2, the first 10 terms will be: | ||
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1,2,3,5,8,13,21,34,55,89,.. | ||
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By considering the terms in the Fibonacci sequence whose values do not exceed | ||
n, find the sum of the even-valued terms. e.g. for n=10, we have {2,8}, sum is | ||
10. | ||
""" | ||
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def solution(n): | ||
"""Returns the sum of all fibonacci sequence even elements that are lower | ||
or equals to n. | ||
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>>> solution(10) | ||
10 | ||
>>> solution(15) | ||
10 | ||
>>> solution(2) | ||
2 | ||
>>> solution(1) | ||
0 | ||
>>> solution(34) | ||
44 | ||
""" | ||
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a = [0,1] | ||
i = 0 | ||
while a[i] <= n: | ||
a.append(a[i] + a[i+1]) | ||
if a[i+2] > n: | ||
break | ||
i += 1 | ||
sum = 0 | ||
for j in range(len(a) - 1): | ||
if a[j] % 2 == 0: | ||
sum += a[j] | ||
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return sum | ||
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if __name__ == "__main__": | ||
print(solution(int(input().strip()))) |
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