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46 changes: 46 additions & 0 deletions data_structures/arrays/gas_station.py
Original file line number Diff line number Diff line change
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from typing import list


class Solution:
def can_complete_circuit(self, gas: list[int], cost: list[int]) -> int:

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As there is no test file in this pull request nor any test function or class in the file data_structures/arrays/gas_station.py, please provide doctest for the function can_complete_circuit

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As there is no test file in this pull request nor any test function or class in the file data_structures/arrays/gas_station.py, please provide doctest for the function can_complete_circuit

# Step 1: Initialize variables
# total_gas will keep track of the total balance of gas - cost across all stations

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# current_gas will track the gas balance for the current trip from the starting station

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# start_station will track the potential starting point of the circuit
total_gas = 0
current_gas = 0
start_station = 0

# Step 2: Loop through each gas station
for i in range(len(gas)):
# Calculate the net gas gain/loss at the current station
total_gas += gas[i] - cost[i]
current_gas += gas[i] - cost[i]

# Step 3: If current_gas becomes negative, it means we cannot continue
# the journey from the current start_station, so we update the start_station
# to the next one and reset the current_gas to 0.
if current_gas < 0:
start_station = i + 1 # Move the starting station to the next one
current_gas = 0 # Reset the gas for the new start

# Step 4: Check if the total gas is enough to complete the circuit
# If total_gas is negative, it means the entire circuit cannot be completed
if total_gas < 0:
return -1
else:
# If total_gas is non-negative, return the start_station as the answer
return start_station


# Example usage with hints:

# Example 1:
gas = [1, 2, 3, 4, 5]
cost = [3, 4, 5, 1, 2]

# Step-by-step hint:
# 1. Start from station 3 (index 3), where the gas is 4 and the cost to the next station is 1.

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# 2. Keep tracking the current gas and total gas balance as you move through the stations.

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solution = Solution()
print(solution.can_complete_circuit(gas, cost)) # Output: 3
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