Skip to content

add monotonic queue algorithm #10531

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
wants to merge 4 commits into
base: master
Choose a base branch
from
Open
Changes from 2 commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
39 changes: 39 additions & 0 deletions data_structures/queue/monotonic_queue.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,39 @@
from __future__ import annotations

from double_ended_queue import Deque

arr = [1, 3, -1, -3, 5, 3, 6, 7]
k = 3
expect = [3, 3, 5, 5, 6, 7]


def max_sliding_window(arr: list[float], k: int) -> list[float]:

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Please provide descriptive name for the parameter: k

Copy link
Contributor Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

I changed it to window_size

"""
Given an array of integers nums, there is a sliding window of size k which is moving
from the very left of the array to the very right.
Each time the sliding window of length k moves right by one position.
Return the max sliding window.
>>> max_sliding_window(arr, k) == expect
True
"""
max_val = []
queue = Deque()
for i in range(len(arr)):
# pop the element if the index is outside the window size k
if queue and i - queue._front.val >= k:
queue.popleft()
# keep the queue monotonically decreasing
# so that the max value is always on the top
while queue and arr[i] >= arr[queue._back.val]:
queue.pop()
queue.append(i)
# the maximum value is the first element in queue
if i >= k - 1:
max_val.append(arr[queue._front.val])
return max_val


if __name__ == "__main__":
from doctest import testmod

testmod()