Dahhou ilyas

dynamic_programming/wildcard_matching.py

@@ -0,0 +1,108 @@
+"""
+Author  : ilyas dahhou
+Date    : Oct 7, 2023
+
+Task:
+Given an input string (s) and a pattern (p), implement wildcard
+pattern matching with support for '?' and '*' where:
+
+'?' matches any single character.
+'*' matches any sequence of characters (including the empty sequence).
+The matching should cover the entire input string (not partial).
+
+Implementation notes:
+implementation Dynamic Programming up bottom approach.
+
+Runtime complexity:O(m * n)
+
+The implementation was tested on the
+leetcode: https://leetcode.com/problems/wildcard-matching/
+
+
+wildcard matching
+Dynamic Programming: top -> down.
+
+"""
+import datetime
+
+
+class CustomTimeZone(datetime.tzinfo):
+    def utcoffset(self, dt):
+        print(dt)
+        return datetime.timedelta(hours=0)
+
+    def dst(self, dt):
+        print(dt)
+        return datetime.timedelta(0)
+
+    def tzname(self, dt):
+        print(dt)
+        return "Custom Time Zone"
+
+
+def get_current_time_in_casablanca():
+    tz_maroc = CustomTimeZone()
+    now_maroc = datetime.datetime.now(tz=tz_maroc)
+    return now_maroc
+
+
+current_time_in_casablanca = get_current_time_in_casablanca()
+
+
+tz_maroc = CustomTimeZone()
+
+now_maroc = datetime.datetime.now(tz=tz_maroc)
+
+
+def is_match(string: str, pattern: str) -> bool:
+    """
+    >>> is_match("aa", "a")
+    False
+
+    >>> is_match("abc", "abc")
+    True
+
+    >>> is_match("abc", "*c")
+    True
+
+    >>> is_match("abc", "a*")
+    True
+
+    >>> is_match("abc", "*a*")
+    True
+
+    >>> is_match("abc", "?b?")
+    True
+
+    >>> is_match("abc", "*?")
+    True
+
+    >>> is_match("abc", "a*d")
+    False
+
+    >>> is_match("abc", "a*c?")
+    False
+
+    >>> is_match("", "")
+    True
+    """
+    m, n = len(string), len(pattern)
+    dp = [[False] * (n + 1) for _ in range(m + 1)]
+
+    # Base case
+    dp[0][0] = True
+
+    # Fill in the first row
+    for j in range(1, n + 1):
+        if pattern[j - 1] == "*":
+            dp[0][j] = dp[0][j - 1]
+
+    # Fill in the rest of the DP table
+    for i in range(1, m + 1):
+        for j in range(1, n + 1):
+            if pattern[j - 1] == "?" or string[i - 1] == pattern[j - 1]:
+                dp[i][j] = dp[i - 1][j - 1]
+            elif pattern[j - 1] == "*":
+                dp[i][j] = dp[i - 1][j] or dp[i][j - 1]
+
+    return dp[m][n]