Add solution and test-cases for problem 600

leetcode/501-600/0600.Non-negative-Integers-without-Consecutive-Ones/README.md

@@ -1,28 +1,37 @@
 # [600.Non-negative Integers without Consecutive Ones][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+Given a positive integer `n`, return the number of the integers in the range `[0, n]` whose binary representations **do not** contain consecutive ones.
 
 **Example 1:**
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: n = 5
+Output: 5
+Explanation:
+Here are the non-negative integers <= 5 with their corresponding binary representations:
+0 : 0
+1 : 1
+2 : 10
+3 : 11
+4 : 100
+5 : 101
+Among them, only integer 3 disobeys the rule (two consecutive ones) and the other 5 satisfy the rule.
 ```
 
-## 题意
-> ...
-
-## 题解
+**Example 2:**
 
-### 思路1
-> ...
-Non-negative Integers without Consecutive Ones
-```go
+```
+Input: n = 1
+Output: 2
 ```
 
+**Example 3:**
+
+```
+Input: n = 2
+Output: 3
+```
 
 ## 结语
 

leetcode/501-600/0600.Non-negative-Integers-without-Consecutive-Ones/Solution.go

@@ -1,5 +1,49 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+func nBit(n int) ([]int, int) {
+	a := make([]int, 32)
+	i := 31
+	for n > 0 {
+		a[i] = n & 1
+		n >>= 1
+		i--
+	}
+	return a, i + 1
+}
+
+func dfsBit(preBit, index int, less bool, array []int) int {
+	if index == 32 {
+		return 1
+	}
+	if preBit == 1 {
+		if array[index] == 1 {
+			return dfsBit(0, index+1, true, array)
+		}
+		return dfsBit(0, index+1, less, array)
+	}
+	if array[index] == 1 {
+		return dfsBit(1, index+1, less, array) + dfsBit(0, index+1, true, array)
+	}
+	a := dfsBit(0, index+1, less, array)
+	if less {
+		a += dfsBit(1, index+1, less, array)
+	}
+	return a
+}
+
+func Solution(n int) int {
+	if n <= 2 {
+		return n + 1
+	}
+	bits, startIndex := nBit(n)
+	cnt := 0
+	zero, one := 1, 1
+	for i := 30; i > startIndex; i-- {
+		tmpZero := zero + one
+		tmpOne := zero
+		zero, one = tmpZero, tmpOne
+	}
+	cnt += zero + one
+
+	return cnt + dfsBit(1, startIndex+1, false, bits)
 }

leetcode/501-600/0600.Non-negative-Integers-without-Consecutive-Ones/Solution_test.go

@@ -10,12 +10,13 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		inputs int
+		expect int
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", 5, 5},
+		{"TestCase2", 1, 2},
+		{"TestCase3", 2, 3},
+		{"TestCase4", 999999995, 2178309},
 	}
 
 	//	开始测试
@@ -30,10 +31,10 @@ func TestSolution(t *testing.T) {
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }