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Original file line number Diff line number Diff line change
@@ -1,28 +1,46 @@
# [2948.Make Lexicographically Smallest Array by Swapping Elements][title]

> [!WARNING|style:flat]
> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)

## Description
You are given a **0-indexed** array of **positive** integers `nums` and a **positive** integer `limit`.

In one operation, you can choose any two indices `i` and `j` and swap `nums[i]` and `nums[j]` if `|nums[i] - nums[j]| <= limit`.

Return the **lexicographically smallest array** that can be obtained by performing the operation any number of times.

An array `a` is lexicographically smaller than an array `b` if in the first position where `a` and `b` differ, array a has an element that is less than the corresponding element in `b`. For example, the array `[2,10,3]` is lexicographically smaller than the array `[10,2,3]` because they differ at index `0` and `2 < 10`.


**Example 1:**

```
Input: a = "11", b = "1"
Output: "100"
Input: nums = [1,5,3,9,8], limit = 2
Output: [1,3,5,8,9]
Explanation: Apply the operation 2 times:
- Swap nums[1] with nums[2]. The array becomes [1,3,5,9,8]
- Swap nums[3] with nums[4]. The array becomes [1,3,5,8,9]
We cannot obtain a lexicographically smaller array by applying any more operations.
Note that it may be possible to get the same result by doing different operations.
```

## 题意
> ...
**Example 2:**

## 题解

### 思路1
> ...
Make Lexicographically Smallest Array by Swapping Elements
```go
```
Input: nums = [1,7,6,18,2,1], limit = 3
Output: [1,6,7,18,1,2]
Explanation: Apply the operation 3 times:
- Swap nums[1] with nums[2]. The array becomes [1,6,7,18,2,1]
- Swap nums[0] with nums[4]. The array becomes [2,6,7,18,1,1]
- Swap nums[0] with nums[5]. The array becomes [1,6,7,18,1,2]
We cannot obtain a lexicographically smaller array by applying any more operations.
```

**Example 3:**

```
Input: nums = [1,7,28,19,10], limit = 3
Output: [1,7,28,19,10]
Explanation: [1,7,28,19,10] is the lexicographically smallest array we can obtain because we cannot apply the operation on any two indices.
```

## 结语

Expand Down
Original file line number Diff line number Diff line change
@@ -1,5 +1,46 @@
package Solution

func Solution(x bool) bool {
return x
import "sort"

func Solution(nums []int, limit int) []int {
l := len(nums)
dst := make([]int, l)
for i := range l {
dst[i] = i
}
sort.Slice(dst, func(i, j int) bool {
a, b := nums[dst[i]], nums[dst[j]]
if a == b {
return i < j
}
return a < b
})
groupIndies := map[int][]int{
0: []int{1, dst[0]},
}
numGroup := make([]int, len(nums))

g := 0

for i := 1; i < l; i++ {
if diff := nums[dst[i]] - nums[dst[i-1]]; diff > limit {
g++
}

numGroup[dst[i]] = g
if _, ok := groupIndies[g]; !ok {
groupIndies[g] = []int{1}
}
groupIndies[g] = append(groupIndies[g], dst[i])
}

r := make([]int, l)
for i := range nums {
group := numGroup[i]
indies := groupIndies[group]
idx := indies[indies[0]]
indies[0]++
r[i] = nums[idx]
}
return r
}
Original file line number Diff line number Diff line change
Expand Up @@ -10,30 +10,31 @@ func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
nums []int
limit int
expect []int
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", []int{1, 5, 3, 9, 8}, 2, []int{1, 3, 5, 8, 9}},
{"TestCase2", []int{1, 7, 6, 18, 2, 1}, 3, []int{1, 6, 7, 18, 1, 2}},
{"TestCase3", []int{1, 7, 28, 19, 10}, 3, []int{1, 7, 28, 19, 10}},
}

// 开始测试
for i, c := range cases {
t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
got := Solution(c.inputs)
got := Solution(c.nums, c.limit)
if !reflect.DeepEqual(got, c.expect) {
t.Fatalf("expected: %v, but got: %v, with inputs: %v",
c.expect, got, c.inputs)
t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
c.expect, got, c.nums, c.limit)
}
})
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
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