commit go 203

Author: xiao2shiqi

go/203.go

@@ -0,0 +1,44 @@
+package main
+
+import "fmt"
+
+/**
+ * LC#203 移除链表元素 Remove Linked List Elements
+ * Link：https://leetcode-cn.com/problems/remove-linked-list-elements/
+ * 思路1（optimum solution 最优解）：初始化一个 sentinel 遍历检查链表 head 链表，判断 tmp.val == val 就放弃当前引用，指向下一个引用 简单粗暴。从官方答案来看这应该也是最优解了
+ */
+type ListNode struct {
+	Val  int
+	Next *ListNode
+}
+
+func removeElements(head *ListNode, val int) *ListNode {
+	sentinel := &ListNode{0, head}
+	for tmp := sentinel; tmp.Next != nil; {
+		if tmp.Next.Val == val {
+			tmp.Next = tmp.Next.Next
+		} else {
+			tmp = tmp.Next
+		}
+	}
+	return sentinel.Next
+}
+
+func main() {
+
+	// build a simple linked
+	n7 := ListNode{6, nil}
+	n6 := ListNode{5, &n7}
+	n5 := ListNode{4, &n6}
+	n4 := ListNode{3, &n5}
+	n3 := ListNode{6, &n4}
+	n2 := ListNode{2, &n3}
+	n1 := ListNode{1, &n2}
+	cur := removeElements(&n1, 6)
+
+	// Output Linked ...
+	for cur != nil {
+		fmt.Printf("cur %v  , val %d \n", cur, cur.Val)
+		cur = cur.Next
+	}
+}