kit 把 ListNode 的处理函数，变成公开的。

Author: aQua

kit/ListNode.go

@@ -11,10 +11,11 @@ type ListNode struct {
 	Next *ListNode
 }
 
-// convert *ListNode to []int
-func l2s(head *ListNode) []int {
+// List2Slice convert List to []int
+func List2Slice(head *ListNode) []int {
 	// 链条深度限制，链条深度超出此限制，会 panic
 	limit := 100
+
 	times := 0
 
 	res := []int{}
@@ -32,15 +33,16 @@ func l2s(head *ListNode) []int {
 	return res
 }
 
-// convert []int to *ListNode
-func s2l(nums []int) *ListNode {
+// Slice2List convert []int to List
+func Slice2List(nums []int) *ListNode {
 	if len(nums) == 0 {
 		return nil
 	}
 
 	res := &ListNode{
 		Val: nums[0],
 	}
+
 	temp := res
 	for i := 1; i < len(nums); i++ {
 		temp.Next = &ListNode{

kit/ListNode_test.go

@@ -8,7 +8,7 @@ import (
 
 func Test_l2s(t *testing.T) {
 	ast := assert.New(t)
-	ast.Equal([]int{}, l2s(nil), "输入nil，没有返回[]int{}")
+	ast.Equal([]int{}, List2Slice(nil), "输入nil，没有返回[]int{}")
 
 	one2three := &ListNode{
 		Val: 1,
@@ -19,18 +19,18 @@ func Test_l2s(t *testing.T) {
 			},
 		},
 	}
-	ast.Equal([]int{1, 2, 3}, l2s(one2three), "没有成功地转换成[]int")
+	ast.Equal([]int{1, 2, 3}, List2Slice(one2three), "没有成功地转换成[]int")
 
 	limit := 100
-	overLimitList := s2l(make([]int, limit+1))
-	ast.Panics(func() { l2s(overLimitList) }, "转换深度超过 %d 限制的链条，没有 panic", limit)
+	overLimitList := Slice2List(make([]int, limit+1))
+	ast.Panics(func() { List2Slice(overLimitList) }, "转换深度超过 %d 限制的链条，没有 panic", limit)
 }
 
 func Test_s2l(t *testing.T) {
 	ast := assert.New(t)
-	ast.Nil(s2l([]int{}), "输入[]int{}，没有返回nil")
+	ast.Nil(Slice2List([]int{}), "输入[]int{}，没有返回nil")
 
-	ln := s2l([]int{1, 2, 3, 4, 5, 6, 7, 8, 9})
+	ln := Slice2List([]int{1, 2, 3, 4, 5, 6, 7, 8, 9})
 	i := 1
 	for ln != nil {
 		ast.Equal(i, ln.Val, "对应的值不对")