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| 1 | +// Problem Number: 2179 |
| 2 | + |
| 3 | +// Count Good Triplet in an Array. |
| 4 | + |
| 5 | +class FenwickTree { |
| 6 | + public FenwickTree(int n) { |
| 7 | + sums = new int[n + 1]; |
| 8 | + } |
| 9 | + |
| 10 | + public void add(int i, int delta) { |
| 11 | + while (i < sums.length) { |
| 12 | + sums[i] += delta; |
| 13 | + i += lowbit(i); |
| 14 | + } |
| 15 | + } |
| 16 | + |
| 17 | + public int get(int i) { |
| 18 | + int sum = 0; |
| 19 | + while (i > 0) { |
| 20 | + sum += sums[i]; |
| 21 | + i -= lowbit(i); |
| 22 | + } |
| 23 | + return sum; |
| 24 | + } |
| 25 | + |
| 26 | + private int[] sums; |
| 27 | + |
| 28 | + private static int lowbit(int i) { |
| 29 | + return i & -i; |
| 30 | + } |
| 31 | +} |
| 32 | + |
| 33 | +class Solution { |
| 34 | + public long goodTriplets(int[] nums1, int[] nums2) { |
| 35 | + final int n = nums1.length; |
| 36 | + long ans = 0; |
| 37 | + Map<Integer, Integer> numToIndex = new HashMap<>(); |
| 38 | + int[] arr = new int[n]; |
| 39 | + int[] leftSmaller = new int[n]; |
| 40 | + int[] rightLarger = new int[n]; |
| 41 | + FenwickTree tree1 = new FenwickTree(n); |
| 42 | + FenwickTree tree2 = new FenwickTree(n); |
| 43 | + |
| 44 | + for (int i = 0; i < n; ++i) |
| 45 | + numToIndex.put(nums1[i], i); |
| 46 | + |
| 47 | + for (int i = 0; i < n; ++i) |
| 48 | + arr[i] = numToIndex.get(nums2[i]); |
| 49 | + |
| 50 | + for (int i = 0; i < n; ++i) { |
| 51 | + leftSmaller[i] = tree1.get(arr[i]); |
| 52 | + tree1.add(arr[i] + 1, 1); |
| 53 | + } |
| 54 | + |
| 55 | + for (int i = n - 1; i >= 0; --i) { |
| 56 | + rightLarger[i] = tree2.get(n) - tree2.get(arr[i]); |
| 57 | + tree2.add(arr[i] + 1, 1); |
| 58 | + } |
| 59 | + |
| 60 | + for (int i = 0; i < n; ++i) |
| 61 | + ans += (long) leftSmaller[i] * rightLarger[i]; |
| 62 | + |
| 63 | + return ans; |
| 64 | + } |
| 65 | +} |
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