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| 1 | +//212. Word Search II |
| 2 | +class TrieNode { |
| 3 | + public TrieNode[] children = new TrieNode[26]; |
| 4 | + public String word; |
| 5 | +} |
| 6 | + |
| 7 | +class Solution { |
| 8 | + public List<String> findWords(char[][] board, String[] words) { |
| 9 | + for (final String word : words) |
| 10 | + insert(word); |
| 11 | + |
| 12 | + List<String> ans = new ArrayList<>(); |
| 13 | + |
| 14 | + for (int i = 0; i < board.length; ++i) |
| 15 | + for (int j = 0; j < board[0].length; ++j) |
| 16 | + dfs(board, i, j, root, ans); |
| 17 | + |
| 18 | + return ans; |
| 19 | + } |
| 20 | + |
| 21 | + private TrieNode root = new TrieNode(); |
| 22 | + |
| 23 | + private void insert(final String word) { |
| 24 | + TrieNode node = root; |
| 25 | + for (final char c : word.toCharArray()) { |
| 26 | + final int i = c - 'a'; |
| 27 | + if (node.children[i] == null) |
| 28 | + node.children[i] = new TrieNode(); |
| 29 | + node = node.children[i]; |
| 30 | + } |
| 31 | + node.word = word; |
| 32 | + } |
| 33 | + |
| 34 | + private void dfs(char[][] board, int i, int j, TrieNode node, List<String> ans) { |
| 35 | + if (i < 0 || i == board.length || j < 0 || j == board[0].length) |
| 36 | + return; |
| 37 | + if (board[i][j] == '*') |
| 38 | + return; |
| 39 | + |
| 40 | + final char c = board[i][j]; |
| 41 | + TrieNode child = node.children[c - 'a']; |
| 42 | + if (child == null) |
| 43 | + return; |
| 44 | + if (child.word != null) { |
| 45 | + ans.add(child.word); |
| 46 | + child.word = null; |
| 47 | + } |
| 48 | + |
| 49 | + board[i][j] = '*'; |
| 50 | + dfs(board, i + 1, j, child, ans); |
| 51 | + dfs(board, i - 1, j, child, ans); |
| 52 | + dfs(board, i, j + 1, child, ans); |
| 53 | + dfs(board, i, j - 1, child, ans); |
| 54 | + board[i][j] = c; |
| 55 | + } |
| 56 | +} |
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