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给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。
给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。
示例:
输入:"23" 输出:["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"]. 说明: 尽管上面的答案是按字典序排列的,但是你可以任意选择答案输出的顺序。
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/letter-combinations-of-a-phone-number 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
每次递归中都对当前数字所代表的的字母全部列出来,拼在已完成的字符后面,再交给下一次递归。通过 index 下标来判断是否完成,一旦长度符合,就放入结果数组中。
/** * @param {string} digits * @return {string[]} */ let letterMap = [ " ", //0 "", //1 "abc", //2 "def", //3 "ghi", //4 "jkl", //5 "mno", //6 "pqrs", //7 "tuv", //8 "wxyz" //9 ] let letterCombinations = function (digits) { let res = [] if (digits === "") { return res } let findCombinations = (index, str) => { if (digits.length === index) { res.push(str) return } let char = digits[index] let letters = letterMap[Number(char)] for (let i = 0; i < letters.length; i++) { let letter = letters[i] findCombinations(index + 1, `${str}${letter}`) } } findCombinations(0, "") return res };
The text was updated successfully, but these errors were encountered:
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给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。
给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。
示例:
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/letter-combinations-of-a-phone-number
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
思路
每次递归中都对当前数字所代表的的字母全部列出来,拼在已完成的字符后面,再交给下一次递归。通过 index 下标来判断是否完成,一旦长度符合,就放入结果数组中。
The text was updated successfully, but these errors were encountered: