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Gonzalo Diaz
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[Hacker Rank]: Compare the Triplets solved ✓
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# [Compare the Triplets](https://www.hackerrank.com/challenges/compare-the-triplets)
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Difficulty: #easy
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Category: #warmup
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Alice and Bob each created one problem for HackerRank. A reviewer rates the two
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challenges, awarding points on a scale from 1 to 100 for three categories:
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problem clarity, originality, and difficulty.
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The rating for Alice's challenge is the triplet $ a = (a[0], a[1], a[2]) $,
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and the rating for Bob's challenge is the triplet $ b = (b[0], b[1], b[2]) $.
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The task is to find their comparison points by comparing $ a[0] $ with
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$ b[0] $, $ a[1] $ with $ b[1] $, and $ a[2] $ with $ b[2] $.
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- If $ a[i] > b[i] $, then Alice is awarded $ 1 $ point.
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- If $ a[i] < b[i] $, then Bob is awarded $ 1 $ point.
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- If $ a[i] = b[i] $, then neither person receives a point.
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Comparison points is the total points a person earned.
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Given a and b, determine their respective comparison points.
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## Example
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$ a = [1, 2, 3] $ \
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$ b = [3, 2, 1] $
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- For elements \*0\*, Bob is awarded a point because $ a[0] $.
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- For the equal elements $ a[1] $ and $ b[1] $, no points are earned.
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- Finally, for elements $ 2 $, $ a[2] > b[2] $ so Alice receives a point.
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The return array is $ [1, 1] $ with Alice's score first and Bob's second.
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## Function Description
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Complete the function compareTriplets in the editor below.
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compareTriplets has the following parameter(s):
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- int a[3]: Alice's challenge rating
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- int b[3]: Bob's challenge rating
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## Return
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- int[2]: Alice's score is in the first position, and Bob's score is in the second.
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## Input Format
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The first line contains 3 space-separated integers, $ a[0] $, $ a[1] $, and
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$ a[2] $, the respective values in triplet a.
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The second line contains 3 space-separated integers, $ b[0] $, $ b[1] $, and
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$ b[2] $, the respective values in triplet b.
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## Constraints
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- $ 1 \leq a[i] \leq 100 $
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- $ 1 \leq b[i] \leq 100 $
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## Sample Input 0
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```text
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5 6 7
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3 6 10
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```
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## Sample Output 0
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```text
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1 1
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```
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## Explanation 0
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In this example:
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- $ a = (a[0], a[1], a[2]) = (5, 6, 7) $
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- $ b = (b[0], b[1], b[2]) = (3, 6, 10) $
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Now, let's compare each individual score:
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- $ a[0] > b[0] $, so Alice receives $ 1 $ point. \
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- $ a[1] = b[1] $, so nobody receives a point. \
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- $ a[2] < b[2] $, so Bob receives $ 1 $ point.
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Alice's comparison score is $ 1 $, and Bob's comparison score is $ 1 $.
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Thus, we return the array $ [1, 1] $.
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## Sample Input 1
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```text
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17 28 30
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99 16 8
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```
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## Sample Output 1
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```text
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2 1
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```
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## Explanation 1
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Comparing the *0th* elements, $ 17 < 99 $ so Bob receives a point.
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Comparing the *1st* and *2nd* elements $ 28 > 16 $ and $ 30 > 8 $ so Alice
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receives two points.
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The return array is $ [2, 1] $.
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/**
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* @link Problem definition [[docs/hackerrank/warmup/compareTriplets.md]]
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*/
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package hackerrank
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import (
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"errors"
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utils "gon.cl/algorithm-exercises/src/utils"
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)
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func CompareTriplets(a []int, b []int) ([]int, error) {
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if len(a) != len(b) {
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return nil, errors.New("math: square root of negative number")
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}
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var awards = []int{0, 0}
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for i := 0; i < len(a); i++ {
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if a[i] > b[i] {
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awards[0] = awards[0] + 1
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}
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if a[i] < b[i] {
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awards[1] = awards[1] + 1
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}
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}
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utils.Info("SolveMeFirst answer => %v", awards)
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return awards, nil
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}
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package hackerrank
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import (
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"fmt"
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"testing"
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"github.com/stretchr/testify/assert"
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)
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func TestCompareTripletsBorderCase(t *testing.T) {
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expectedSolution := []int{1, 1}
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a := []int{1}
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b := []int{2, 3}
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testname := fmt.Sprintf("CompareTriplets(%d, %d) => %v \n", a, b, expectedSolution)
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t.Run(testname, func(t *testing.T) {
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ans, err := CompareTriplets(a, b)
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assert.Nil(t, ans)
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assert.Error(t, err)
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})
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}
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func TestCompareTriplets(t *testing.T) {
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expectedSolution := []int{1, 1}
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a := []int{5, 6, 7}
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b := []int{3, 6, 10}
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testname := fmt.Sprintf("CompareTriplets(%d, %d) => %v \n", a, b, expectedSolution)
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t.Run(testname, func(t *testing.T) {
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ans, err := CompareTriplets(a, b)
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assert.Equal(t, expectedSolution, ans)
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assert.Nil(t, err)
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})
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}

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