A code example doesn't work

[ShapelessCat]

In the section "Transparent Inline Methods" of Scala 3 Macro Tutorial / Inline.md, there is a code example:

transparent inline def default(inline name: String): Any =
  inline if name == "Int" then 0
  else inline if name == "String" then ""
  else ...

I run default("Int") in console (Scala 3.0.0-M2), and I see this error message:

default("Int")
1 |default("Int")
  |^^^^^^^^^^^^^^
  |Cannot reduce `inline if` because its condition is not a constant value: "Int".==("Int")
  | This location contains code that was inlined from rs$line$1:2

I also tried to implement it with inline match, and it works:

transparent inline def default(inline name: String): Any =
  inline name match
    case "Int"      => 0
    case "String" => ""
    case _            => ...

It seems this difference between inline if and inline match is not reasonable, but I'm not sure.

[ShapelessCat]

I update the description.
Is this a bug?

[nicolasstucki]

It is a bug