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Is there a way to remove the Option<> in the generated code of function pointer member in struct?
Option<>
struct Okela { int *some_ptr; int (*get_some_val)(int a, int b); };
pub struct Okela { pub some_ptr: *mut i32, pub get_some_val: ::std::option::Option< unsafe extern "C" fn(a: ::std::os::raw::c_int, b: ::std::os::raw::c_int), >, }
... pub get_some_val: unsafe extern "C" fn(a: ::std::os::raw::c_int, b: ::std::os::raw::c_int),
The text was updated successfully, but these errors were encountered:
duplicated of #1278
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Is there a way to remove the
Option<>
in the generated code of function pointer member in struct?Input C/C++ Header
Actual Results
Expected Results
The text was updated successfully, but these errors were encountered: