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DOC: .get_slice_bound in MultiIndex needs documentation. (pandas-dev#29967)
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pandas/core/indexes/multi.py

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@@ -1,6 +1,7 @@
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from collections import OrderedDict
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import datetime
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from sys import getsizeof
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from typing import Tuple, Union
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import warnings
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import numpy as np
@@ -2441,7 +2442,53 @@ def reindex(self, target, method=None, level=None, limit=None, tolerance=None):
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return target, indexer
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def get_slice_bound(self, label, side, kind):
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def get_slice_bound(
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self, label: Union[object, Tuple[object, ...]], side: str, kind: str
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) -> int:
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"""
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For an ordered MultiIndex, compute slice bound
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that corresponds to given label.
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Returns leftmost (one-past-the-rightmost if `side=='right') position
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of given label.
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Parameters
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----------
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label : object or tuple of objects
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side : {'left', 'right'}
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kind : {'ix', 'loc', 'getitem'}
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Returns
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-------
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int
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Index of label.
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Notes
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-----
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This method only works if level 0 index of the MultiIndex is lexsorted.
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Examples
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--------
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>>> mi = pd.MultiIndex.from_arrays([list('abbc'), list('gefd')])
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Get the locations from the leftmost 'b' in the first level
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until the end of the multiindex:
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>>> mi.get_slice_bound('b', side="left", kind="ix")
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1
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Like above, but if you get the locations from the rightmost
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'b' in the first level and 'f' in the second level:
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>>> mi.get_slice_bound(('b','f'), side="right", kind="ix")
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3
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See Also
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--------
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MultiIndex.get_loc : Get location for a label or a tuple of labels.
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MultiIndex.get_locs : Get location for a label/slice/list/mask or a
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sequence of such.
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"""
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if not isinstance(label, tuple):
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label = (label,)

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