diff --git a/doc/source/groupby.rst b/doc/source/groupby.rst
index 41539b5ce283e..d2f60b791eb7c 100644
--- a/doc/source/groupby.rst
+++ b/doc/source/groupby.rst
@@ -722,4 +722,14 @@ To see the order in which each row appears within its group, use the
 
    df.groupby('A').cumcount()
 
-   df.groupby('A').cumcount(ascending=False)  # kwarg only
\ No newline at end of file
+   df.groupby('A').cumcount(ascending=False)  # kwarg only
+   
+Examples
+~~~~~~~~
+
+Regroup columns of a DataFrame according to their sum, and sum the aggregated ones.
+
+.. ipython:: python
+   
+   df = pd.DataFrame({'a':[1,0,0], 'b':[0,1,0], 'c':[1,0,0], 'd':[2,3,4]})
+   df.groupby(df.sum(), axis=1).sum()