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xref: #7356
API like:
df.nlargest('column_name', 3)
impl like:
def nlargest(self, col, n): return self.loc[self[col].nlargest(n).index]
cc @hayd
The text was updated successfully, but these errors were encountered:
@jreback i think actually you can do you something like and you can have a partial nested sort ...
def nlargest(self, columns, n): return self.loc[self[columns[0]].nlargest(n).index].sort(columns)
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i'll move to 0.15 i think maybe mull over a bit
cpcloud
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xref: #7356
API like:
impl like:
cc @hayd
The text was updated successfully, but these errors were encountered: