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Hi @bbennett36 - does df.groupby(...).size() / df.shape[0] work for you? If so, I think this can be closed, I don't think it's worth adding an extra parameter in size for this
groupby.size()
should have the ability to "normalize" the results and return them as a percentage.To accomplish this result with a
groupby.size()
you have to do the following -Is there a way to add a feature to include this as a parameter in
.size()
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