to_timedelta str int discrepancy

[harishmk]

Code Sample, a copy-pastable example if possible

assert pd.to_timedelta(1,unit='s') == pd.to_timedelta('1',unit='s')

fails

>>> pd.to_timedelta(20000,unit='s')
Timedelta('0 days 05:33:20')

>>> pd.to_timedelta('20000',unit='s')
Timedelta('0 days 00:00:00.000020')

Problem description

it looks like the unit parameter has no effect in pd.to_timedelta('1',unit='s')

Expected Output

Output of pd.show_versions()

INSTALLED VERSIONS

commit : None
python : 3.6.3.final.0
python-bits : 64
OS : Linux
OS-release : 3.10.0-957.27.2.el7.x86_64
machine : x86_64
processor : x86_64
byteorder : little
LC_ALL : None
LANG : en_US.UTF-8
LOCALE : en_US.UTF-8

pandas : 0.25.3
numpy : 1.16.4
pytz : 2019.1
dateutil : 2.8.0
pip : 19.3.1
setuptools : 41.0.1
Cython : 0.29.13
pytest : None
hypothesis : None
sphinx : None
blosc : None
feather : None
xlsxwriter : None
lxml.etree : 4.3.3
html5lib : 1.0.1
pymysql : None
psycopg2 : 2.8.3 (dt dec pq3 ext lo64)
jinja2 : 2.10.1
IPython : 7.5.0
pandas_datareader: None
bs4 : 4.8.0
bottleneck : None
fastparquet : None
gcsfs : None
lxml.etree : 4.3.3
matplotlib : 3.1.1
numexpr : None
odfpy : None
openpyxl : None
pandas_gbq : None
pyarrow : 0.13.0
pytables : None
s3fs : None
scipy : None
sqlalchemy : 1.3.7
tables : None
xarray : None
xlrd : 1.2.0
xlwt : None
xlsxwriter : None

[mroeschke]

Thanks for the report. Duplicate of #12136