"npmat @ pdseries" should be equivalent to "npmat @ pdseries.values" #23411
Labels
Algos
Non-arithmetic algos: value_counts, factorize, sorting, isin, clip, shift, diff
Numeric Operations
Arithmetic, Comparison, and Logical operations
Code Sample
Problem description
Maybe there is a good explanation but I did not expect this.
It is unexpected that
npmat @ pdseries
is NOT equivalent tonpmat @ pdseries.values
.It is unexpected that
npmat @ pdseries
, is equvivalent topdseries.values @ npmat
.Expected Output
nothing
Output of
pd.show_versions()
[paste the output of
pd.show_versions()
here below this line]INSTALLED VERSIONS
commit: None
python: 3.6.3.final.0
python-bits: 64
OS: Windows
OS-release: 10
machine: AMD64
processor: Intel64 Family 6 Model 158 Stepping 9, GenuineIntel
byteorder: little
LC_ALL: None
LANG: None
LOCALE: None.None
pandas: 0.23.4
pytest: 3.7.1
pip: 18.1
setuptools: 36.5.0.post20170921
Cython: 0.26.1
numpy: 1.14.5
scipy: 1.1.0
pyarrow: None
xarray: None
IPython: 6.1.0
sphinx: 1.6.3
patsy: 0.4.1
dateutil: 2.6.1
pytz: 2017.2
blosc: None
bottleneck: 1.2.1
tables: 3.4.2
numexpr: 2.6.2
feather: None
matplotlib: 2.1.0
openpyxl: 2.4.8
xlrd: 1.1.0
xlwt: 1.3.0
xlsxwriter: 1.0.2
lxml: 4.1.0
bs4: 4.6.0
html5lib: 0.999999999
sqlalchemy: 1.1.13
pymysql: None
psycopg2: None
jinja2: 2.9.6
s3fs: None
fastparquet: None
pandas_gbq: None
pandas_datareader: None
The text was updated successfully, but these errors were encountered: