Update 602. Friend Requests II.sql

Author: iamAntimPal

LeetCode SQL 50 Solution/602. Friend Requests II.sql

@@ -53,3 +53,15 @@ Follow up: In the real world, multiple people could have the same most number of
 
 
 
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT requester_id, accepter_id FROM RequestAccepted
+        UNION ALL
+        SELECT accepter_id, requester_id FROM RequestAccepted
+    )
+SELECT requester_id AS id, COUNT(1) AS num
+FROM T
+GROUP BY 1
+ORDER BY 2 DESC
+LIMIT 1;