A binary string is monotone increasing if it consists of some number of 0
's (possibly none), followed by some number of 1
's (also possibly none).
You are given a binary string s
. You can flip s[i]
changing it from 0
to 1
or from 1
to 0
.
Return the minimum number of flips to make s
monotone increasing.
Input: s = "00110" Output: 1 Explanation: We flip the last digit to get 00111.
Input: s = "010110" Output: 2 Explanation: We flip to get 011111, or alternatively 000111.
Input: s = "00011000" Output: 2 Explanation: We flip to get 00000000.
1 <= s.length <= 105
s[i]
is either'0'
or'1'
.
impl Solution {
pub fn min_flips_mono_incr(s: String) -> i32 {
let s = s.as_bytes();
let mut count = s.iter().filter(|&&c| c == b'0').count() as i32;
let mut ret = count;
for i in 0..s.len() {
count += (s[i] == b'1') as i32 - (s[i] == b'0') as i32;
ret = ret.min(count);
}
ret
}
}