In the "100 game" two players take turns adding, to a running total, any integer from 1
to 10
. The player who first causes the running total to reach or exceed 100 wins.
What if we change the game so that players cannot re-use integers?
For example, two players might take turns drawing from a common pool of numbers from 1 to 15 without replacement until they reach a total >= 100.
Given two integers maxChoosableInteger
and desiredTotal
, return true
if the first player to move can force a win, otherwise, return false
. Assume both players play optimally.
Input: maxChoosableInteger = 10, desiredTotal = 11 Output: false Explanation: No matter which integer the first player choose, the first player will lose. The first player can choose an integer from 1 up to 10. If the first player choose 1, the second player can only choose integers from 2 up to 10. The second player will win by choosing 10 and get a total = 11, which is >= desiredTotal. Same with other integers chosen by the first player, the second player will always win.
Input: maxChoosableInteger = 10, desiredTotal = 0 Output: true
Input: maxChoosableInteger = 10, desiredTotal = 1 Output: true
1 <= maxChoosableInteger <= 20
0 <= desiredTotal <= 300
from functools import cache
class Solution:
def canIWin(self, maxChoosableInteger: int, desiredTotal: int) -> bool:
@cache
def canIWinWithUsed(usedmask: int) -> bool:
total = sum(i + 1 for i in range(maxChoosableInteger)
if (usedmask >> i) & 1 == 1)
for i in range(maxChoosableInteger):
if (usedmask >> i) & 1 == 0:
if total + i + 1 >= desiredTotal or not canIWinWithUsed(usedmask | (1 << i)):
return True
return False
return sum(range(1, maxChoosableInteger + 1)) >= desiredTotal and canIWinWithUsed(0)