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44. Wildcard Matching

Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*' where:

  • '?' Matches any single character.
  • '*' Matches any sequence of characters (including the empty sequence).

The matching should cover the entire input string (not partial).

Example 1:

Input: s = "aa", p = "a"
Output: false
Explanation: "a" does not match the entire string "aa".

Example 2:

Input: s = "aa", p = "*"
Output: true
Explanation: '*' matches any sequence.

Example 3:

Input: s = "cb", p = "?a"
Output: false
Explanation: '?' matches 'c', but the second letter is 'a', which does not match 'b'.

Constraints:

  • 0 <= s.length, p.length <= 2000
  • s contains only lowercase English letters.
  • p contains only lowercase English letters, '?' or '*'.

Solutions (Rust)

1. Solution

impl Solution {
    pub fn is_match(s: String, p: String) -> bool {
        let s = s.as_bytes();
        let p = p.as_bytes();
        let mut dp = vec![false; s.len() + 1];
        dp[0] = true;

        for i in 1..=p.len() {
            let mut tmp = vec![false; s.len() + 1];
            let mut prefix_or = dp[0];

            if p[i - 1] == b'*' {
                tmp[0] = dp[0];
            }
            for j in 1..=s.len() {
                prefix_or |= dp[j];
                match p[i - 1] {
                    b'?' => tmp[j] = dp[j - 1],
                    b'*' => tmp[j] = prefix_or,
                    _ => tmp[j] = p[i - 1] == s[j - 1] && dp[j - 1],
                }
            }

            dp = tmp;
        }

        dp[s.len()]
    }
}