refactor 197

Author: fishercoder1534

database/_197.sql

@@ -1,20 +1 @@
--- Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
---
--- +---------+------------+------------------+
--- | Id(INT) | Date(DATE) | Temperature(INT) |
--- +---------+------------+------------------+
--- |       1 | 2015-01-01 |               10 |
--- |       2 | 2015-01-02 |               25 |
--- |       3 | 2015-01-03 |               20 |
--- |       4 | 2015-01-04 |               30 |
--- +---------+------------+------------------+
--- For example, return the following Ids for the above Weather table:
--- +----+
--- | Id |
--- +----+
--- |  2 |
--- |  4 |
--- +----+
-
-
 select w1.Id from Weather w1, Weather w2 where w1.Temperature > w2.Temperature and to_days(w1.Date) - to_days(w2.date) = 1;