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_316.java
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package com.fishercoder.solutions.firstthousand;
import java.util.ArrayDeque;
import java.util.Deque;
public class _316 {
public static class Solution1 {
/*
* credit: https://discuss.leetcode.com/topic/32259/java-solution-using-stack-with-comments/2
*/
public String removeDuplicateLetters(String s) {
int[] res = new int[26]; // will contain number of occurences of character (i+'a')
boolean[] visited =
new boolean
[26]; // will contain if character (i+'a') is present in current result
// Stack
char[] ch = s.toCharArray();
for (char c : ch) { // count number of occurences of character
res[c - 'a']++;
}
Deque<Character> st = new ArrayDeque<>(); // answer stack
int index;
for (char c : ch) {
index = c - 'a';
res[index]--; // decrement number of characters remaining in the string to be
// analysed
if (visited[index]) {
// if character is already present in stack, dont bother
continue;
}
// if current character is smaller than last character in stack which occurs later
// in the string again
// it can be removed and added later e.g stack = bc remaining string abc then a can
// pop b and then c
while (!st.isEmpty() && c < st.peek() && res[st.peek() - 'a'] != 0) {
visited[st.pop() - 'a'] = false;
}
st.push(c); // add current character and mark it as visited
visited[index] = true;
}
StringBuilder sb = new StringBuilder();
// pop character from stack and build answer string from back
while (!st.isEmpty()) {
sb.insert(0, st.pop());
}
return sb.toString();
}
}
public static class Solution2 {
/*
* Credit: https://discuss.leetcode.com/topic/31404/a-short-o-n-recursive-greedy-solution
*/
public String removeDuplicateLetters(String s) {
int[] count = new int[26];
int pos = 0; // the position for the smallest s[i]
for (int i = 0; i < s.length(); i++) {
count[s.charAt(i) - 'a']++;
}
for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) < s.charAt(pos)) {
pos = i;
}
count[s.charAt(i) - 'a']--;
if (count[s.charAt(i) - 'a'] == 0) {
break;
}
}
return s.length() == 0
? ""
: s.charAt(pos)
+ removeDuplicateLetters(
s.substring(pos + 1).replaceAll("" + s.charAt(pos), ""));
}
}
}