fix: use keywords in type-empty

Author: marionebl

source/rules/type-empty.js

@@ -2,8 +2,9 @@ import ensureNotEmpty from '../library/ensure-not-empty';
 
 export default (parsed, when) => {
 	const negated = when === 'never';
+	const notEmpty = ensureNotEmpty(parsed.type);
 	return [
-		ensureNotEmpty(parsed.type),
+		negated ? notEmpty : !notEmpty,
 		[
 			'type',
 			negated ? 'may not' : 'must',

test/rules/type-empty.js

@@ -12,7 +12,7 @@ const parsed = {
 	filled: parse(messages.filled)
 };
 
-test.failing('without type should succeed for empty keyword', t => {
+test('without type should succeed for empty keyword', t => {
 	const [actual] = typeEmpty(parsed.empty);
 	const expected = true;
 	t.is(actual, expected);
@@ -24,13 +24,13 @@ test('without type should fail for "never"', t => {
 	t.is(actual, expected);
 });
 
-test.failing('without type should succeed for "always"', t => {
+test('without type should succeed for "always"', t => {
 	const [actual] = typeEmpty(parsed.empty, 'always');
 	const expected = true;
 	t.is(actual, expected);
 });
 
-test.failing('with type fail for empty keyword', t => {
+test('with type fail for empty keyword', t => {
 	const [actual] = typeEmpty(parsed.filled);
 	const expected = false;
 	t.is(actual, expected);
@@ -42,7 +42,7 @@ test('with type succeed for "never"', t => {
 	t.is(actual, expected);
 });
 
-test.failing('with type fail for "always"', t => {
+test('with type fail for "always"', t => {
 	const [actual] = typeEmpty(parsed.filled, 'always');
 	const expected = false;
 	t.is(actual, expected);