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| 1 | +// https://leetcode.com/problems/special-positions-in-a-binary-matrix |
| 2 | +// T: O(n * m) |
| 3 | +// S: O(n + m) |
| 4 | + |
| 5 | +import java.util.Arrays; |
| 6 | + |
| 7 | +public class SpecialPositionInABinaryMatrix { |
| 8 | + public int numSpecial(int[][] matrix) { |
| 9 | + final int[] rowSum = getRowSum(matrix); |
| 10 | + final ColumnSumData columnSumData = getColumnSum(matrix); |
| 11 | + final int[] columnSumOneRowIndex = columnSumData.oneIndex; |
| 12 | + final int[] columnSum = columnSumData.sum; |
| 13 | + int specialPositions = 0; |
| 14 | + for (int i = 0 ; i < columnSum.length ; i++) { |
| 15 | + if (columnSum[i] == 1 && rowSum[columnSumOneRowIndex[i]] == 1) { |
| 16 | + specialPositions++; |
| 17 | + } |
| 18 | + } |
| 19 | + return specialPositions; |
| 20 | + } |
| 21 | + |
| 22 | + private int[] getRowSum(int[][] matrix) { |
| 23 | + final int[] sum = new int[matrix.length]; |
| 24 | + for (int i = 0 ; i < sum.length ; i++) { |
| 25 | + sum[i] = Arrays.stream(matrix[i]).sum(); |
| 26 | + } |
| 27 | + return sum; |
| 28 | + } |
| 29 | + |
| 30 | + private ColumnSumData getColumnSum(int[][] matrix) { |
| 31 | + final int[] sum = new int[matrix[0].length]; |
| 32 | + final int[] indexes = new int[sum.length]; |
| 33 | + for (int i = 0 ; i < sum.length ; i++) { |
| 34 | + for (int row = 0 , index = 0 ; row < matrix.length ; row++) { |
| 35 | + sum[i] += matrix[row][i]; |
| 36 | + if (matrix[row][i] == 1) indexes[i] = row; |
| 37 | + } |
| 38 | + } |
| 39 | + return new ColumnSumData(sum, indexes); |
| 40 | + } |
| 41 | + |
| 42 | + private static final class ColumnSumData { |
| 43 | + private final int[] sum; |
| 44 | + private final int[] oneIndex; |
| 45 | + |
| 46 | + private ColumnSumData(int[] sum, int[] oneIndex) { |
| 47 | + this.sum = sum; |
| 48 | + this.oneIndex = oneIndex; |
| 49 | + } |
| 50 | + } |
| 51 | +} |
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