solves long pressed name

Author: anishLearnsToCode

README.md

@@ -248,8 +248,8 @@
 | 908 | [Smallest Range I](https://leetcode.com/problems/smallest-range-i) | [![Java](assets/java.png)](src/SmallestRangeI.java) |
 | 914 | [X of a kind in a Deck of Cards](https://leetcode.com/problems/x-of-a-kind-in-a-deck-of-cards) | [![Java](assets/java.png)](src/XOfAKindInADeckOfCards.java) |
 | 917 | [Reverse Only Letters](https://leetcode.com/problems/reverse-only-letters) | [![Java](assets/java.png)](src/ReverseOnlyLetters.java) |
-| 922 | [Sort Array by Parity II](https://leetcode.com/problems/sort-array-by-parity-ii) | |
-| 925 | [Long Pressed Name](https://leetcode.com/problems/long-pressed-name) | |
+| 922 | [Sort Array by Parity II](https://leetcode.com/problems/sort-array-by-parity-ii) | [![Java](assets/java.png)](src/SortArrayByParityII.java) |
+| 925 | [Long Pressed Name](https://leetcode.com/problems/long-pressed-name) | [![Java](assets/java.png)](src/LongPressedName.java) |
 | 929 | [Unique Email Addresses](https://leetcode.com/problems/unique-email-addresses) | |
 | 933 | [Number of Recent Calls](https://leetcode.com/problems/number-of-recent-calls) | |
 | 937 | [Reorder Data In Log Files](https://leetcode.com/problems/reorder-data-in-log-files) | |

src/LongPressedName.java

@@ -0,0 +1,21 @@
+public class LongPressedName {
+    public boolean isLongPressedName(String name, String typed) {
+        char current = name.charAt(0);
+        for (int i = 0, j = 0, freq = 0, typedFreq = 0 ; i < name.length() && j < typed.length() ; ) {
+            while (i < name.length() && name.charAt(i) == current) {
+                i++;
+                freq++;
+            }
+            while (j < typed.length() && typed.charAt(j) == current) {
+                j++;
+                typedFreq++;
+            }
+            if (typedFreq < freq) return false;
+            if (i == name.length() && j < typed.length()) return false;
+            if (j == typed.length() && i < name.length()) return false;
+            current = i >= name.length() ? ' ' : name.charAt(i);
+            freq = typedFreq = 0;
+        }
+        return true;
+    }
+}