Find Numbers with Even Number of Digits

Author: anantkaushik

1295-find-numbers-with-even-number-of-digits.py

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+"""
+Problem Link: https://leetcode.com/problems/find-numbers-with-even-number-of-digits/
+
+Given an array nums of integers, return how many of them contain an even number of digits.
+ 
+Example 1:
+Input: nums = [12,345,2,6,7896]
+Output: 2
+Explanation: 
+12 contains 2 digits (even number of digits). 
+345 contains 3 digits (odd number of digits). 
+2 contains 1 digit (odd number of digits). 
+6 contains 1 digit (odd number of digits). 
+7896 contains 4 digits (even number of digits). 
+Therefore only 12 and 7896 contain an even number of digits.
+
+Example 2:
+Input: nums = [555,901,482,1771]
+Output: 1 
+Explanation: 
+Only 1771 contains an even number of digits.
+ 
+Constraints:
+1 <= nums.length <= 500
+1 <= nums[i] <= 10^5
+"""
+class Solution:
+    def findNumbers(self, nums: List[int]) -> int:
+      return sum(self.number_of_digits(number) for number in nums)        
+        
+        
+    def number_of_digits(self, n):
+      count = 0
+      while n:
+        count += 1
+        n //= 10
+      return 1 if count % 2 == 0 else 0