DOC: fix SA01,ES01 for pandas.arrays.IntervalArray.right (pandas-dev#60249)

Author: tuhinsharma121

ci/code_checks.sh

@@ -90,7 +90,6 @@ if [[ -z "$CHECK" || "$CHECK" == "docstrings" ]]; then
         -i "pandas.arrays.ArrowExtensionArray PR07,SA01" \
         -i "pandas.arrays.IntegerArray SA01" \
         -i "pandas.arrays.IntervalArray.length SA01" \
-        -i "pandas.arrays.IntervalArray.right SA01" \
         -i "pandas.arrays.NumpyExtensionArray SA01" \
         -i "pandas.arrays.SparseArray PR07,SA01" \
         -i "pandas.arrays.TimedeltaArray PR07,SA01" \

pandas/core/arrays/interval.py

@@ -1269,6 +1269,21 @@ def right(self) -> Index:
         """
         Return the right endpoints of each Interval in the IntervalArray as an Index.
 
+        This property extracts the right endpoints from each interval contained within
+        the IntervalArray. This can be helpful in use cases where you need to work
+        with or compare only the upper bounds of intervals, such as when performing
+        range-based filtering, determining interval overlaps, or visualizing the end
+        boundaries of data segments.
+
+        See Also
+        --------
+        arrays.IntervalArray.left : Return the left endpoints of each Interval in
+            the IntervalArray as an Index.
+        arrays.IntervalArray.mid : Return the midpoint of each Interval in the
+            IntervalArray as an Index.
+        arrays.IntervalArray.contains : Check elementwise if the Intervals contain
+            the value.
+
         Examples
         --------